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calcular delta H 1/2N2 (g) +1/ 2O2 ---->NO(g) dado lo siguiente N2 (g) +3H2 (g) ---->2NH3 (g) deltaH=-91.8kJ 4NH3 (g) +5O2 (g) --->4NO (g) +
calcular delta H
1/2N2 (g) +1/ 2O2 ---->NO(g)
dado lo siguiente
N2 (g) +3H2 (g) ---->2NH3 (g) deltaH=-91.8kJ
4NH3 (g) +5O2 (g) --->4NO (g) + 6H2O (g) deltaH=-906.2kJ
H2 (g) +1/2O2 (g) ----> H2O (g) deltaH=-241.8KJ
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