Calculate Hrxn (in kJ) for the reaction: 2 N2 (g) + 6 H2O (g) 3 O2 (g) + 4 NH3 (g) Hrxn = ? kJ given the following reactions:

Rxn 1: NH3 (g) N2 (g) + H2 (g) H1 = +46 kJ

Rxn 2: 2 H2 (g) + O2 (g) 2 H2O (g) H2 = 484 kJ

Round your answer to the nearest whole number. If your answer is negative, include the sign.