Calculate , in degrees, for a turn taken at 11.82m/s11.82m/s with a radius of of curvature 48.3m48.3m.

(5%) Problem 20: Part of riding a bicycle involves leaning at the correct angle when making a turn; the rst gure in the image carousel shows a rider leaning the bicycle at an angle 6 from the vertical. To be stable, the net force exerted by the ground where it contacts the tire must be on a line passing through the center of gravity. The forces have been summarized with a free-body diagram, as seen in the second gure in the image carousel. The ground exerts a normal force which is equal in magnitude to the combined weight of the bicycle and the rider. The ground additionally exerts a force due to static friction which is parallel to the ground, causing the bicycle to move in a circle. 50% Part (3) Enter an equation for the tangent of the angle between the bicycle and the vertical in terms of the speed of the bicycle, V, the radius of curvature of the turn, r , and the acceleration due to gravity, g. tan(9) = v2/( r g) I/ Correct! $3 50% Part (b) ,in degrees, for a turn taken at 11.8 m/with a radius of of curvature 48 a 6: 17 SOI - lllnl END Degrees O Radians --_- CLEAR Submit | l I give up! Hints: for a deduction. Hints remaining: _ Feedback: deduction per feedback. Grade Summary Deductions Potential 100% Late Work % 100% Late Potential 100% Submissions Attempts remaining: ( per attempt) rimmed view 1 2 3 4