Calculate the flow of the image field...across the solid boundary delimited by the planes x = 0, y = 0 y z = 0 y by the portion of z = 2 - x- yFromcontained in the octante primer. Consider the orientation from the surface to the one that points to the normal field.

Exercicio 5. Calcule o fluxo do campo F(x,y, =) = (x - y's,y' - all;",2-x26,29) atraves da fronteira do solido limitado pelos planos r = 0, y = 0 e = = 0 e pela porcao de = = 2 - x3 - y] contida no primeiro octante. Considere a orientacao da superficie na qual o campo normal aponta para fora