Calculate the following required infiltration for the proposed building

utilizing the crack method ONLY. Recreate this table and fill in all empty

cells in the table provided below as well.$\backslash$table$[[$Room ID:$,$Room Type:,Area $($SF$)$:$,$QTYW$1$:$,$QTY W$2$:$,$QTYD$1$:$,\backslash$table$[[$Total W$1],[$Crack PL$],[$in Ft:$]],\backslash$table$[[$Total W$2],[$Crack PL$],[$in Ft$]],$Crack Method Infiltration Tabie,Actual Heat Loss $($Btu$/$h$)],[\backslash$table$[[$Total D$1],[$Crack PL$],[$in Ft:$]],\backslash$table$[[$Total W$1$ Crack$],[$PL CFM: @$43],[$CFH$/$Ft of Crack$]],\backslash$table$[[$Total W$2$ Crack$],[$PL CFM: @$26],[$CFH$/$Ft of Crack$]],\backslash$table$[[$Total D$1$ Crack PL$],[$CFM: @$122],[$CFH$/$Ft of Crack$]],\backslash$table$[[\backslash$table$[[$Total Crack$],[$Method$],[$Infiltration CFM:$]]]],\backslash$table$[[$Actual Crack$],[$Method$],[$Infiltration CFM:$]]],[$Classroom #$1,$Lecture Classroom,,,,,,,,,,,,,$],[,$Lecture Classroom,,,,,,,,,,,,,$],[$Classroom #$3,$Lecture Classroom,,,,,,,,,,,,,$],[$Classroom #$4,$Lecture Classroom,,,,,,,,,,,,,$],[$Classroom #$5,$Lecture Classroom,,,,,,,,,,,,,$],[,$Lecture Classroom,,,,,,,,,,,,,$],[,$Lecture Classroom,,,,,,,,,,,,,$],[$Classroom #$9,$Lecture Classroom,,,,,,,,,,,,,$],[$Office #$1,$Closed Office Space,,,,,,,,,,,,,$],[$Office #$2,$Closed Office Space,,,,,,,,,,,,,$],[$Office $|{|}_3,$Closed Office Space,,,,,,,,,,,,,$],[$Office #$4,$Closed Office Space,,,,,,,,,,,,,$],[$Office #$5,$Closed Office Space,,,,,,,,,,,,,$],[$Office $+-6,$Closed Office Space,,,,,,,,,,,,,$],[$Office #$7,$Closed Office Space,,,,,,,,,,,,,$],[$Office #$8,$Closed Office Space,,,,,,,,,,,,,$],[$Corridor$,$Circulation Space,,,,,,,,,,,,,$]]$