Calculate the lattice energy of NaBr(s), given the following thermochemical equations, where A/E and AEA are ionization energy and electron affinity, respectively. Na(s) - Na(g) AH, = +107 k] Na(g) - Na+(g) + e- A/E = +496 k] 1/2 Br2(g) - Br(g) AH, = +112 k] Br(g) + e - Br(g) AEA = -325 k] Na(s) + 1/2 Br,(g) - NaBr(s) AH. = -361 k)