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Calculate the mass of each product formed when 33.57g of diborane (B2H6) reacts with excess water: B2H6(g)+H2O(l)H3BO3(s)+H2(g)[unbalanced] Round each of your answers to 4 significant

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Calculate the mass of each product formed when 33.57g of diborane (B2H6) reacts with excess water: B2H6(g)+H2O(l)H3BO3(s)+H2(g)[unbalanced] Round each of your answers to 4 significant figures. Part 1 of 2 Mass of H3BO3 : Part 2 of 2 Mass of H2

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