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Calculate the pH of a 0.0010 M Ba(OH)2 solution. [HO] [H0 OH-]1.0x10-1 pH =-log([0-D [0*] = 10-PM PH [OH-] PON =-log(OH-])} pil+pOH = 14.00 Hod
Calculate the pH of a 0.0010 M Ba(OH)2 solution. [HO] [H0 OH-]1.0x10-1 pH =-log([0-D [0*] = 10-PM PH [OH-] PON =-log(OH-])} pil+pOH = 14.00 Hod Nod-OT = [-NO]
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Organic Chemistry
Authors: Francis A. Carey
4th edition
0072905018, 978-0072905014
