Calculate the standard enthalpy of formation of carbon disulfide $(C{S}_2)$ from its elements, given that

$C_{gr}+O_{2}C{O}_2{H}_{rxn}=-393\mathrm{.}5J\frac{K}{m}ol$

$S+O_{2}S{O}_2{H}_{rxn}=-296\mathrm{.}4K\frac{J}{m}ol$

$C{S}_2+3O_{2}C{O}_2+2S{O}_2{H}_{rxn}=-1073\mathrm{.}6K\frac{J}{m}ol$

a$.87\mathrm{.}3K\frac{J}{m}ol$

b$.8\mathrm{.}73K\frac{J}{m}ol$

c$.187\mathrm{.}3K\frac{J}{m}ol$

d$.287\mathrm{.}3K\frac{J}{m}ol$