Calculate the stopping power of a proton with an energy of 5MeV in water, using hand calculations. Please show all work. a. For this question, use the following values for proton constants, which should be accessible, or given in the lecture content. Additional values can be found in Table 1 below. i. I=74.6eV ii. N=3.381023e/cm3 Considering the considerable difference in mass between an alpha particle and proton, calculate the stopping power of a 5MeV alpha using Table 1 and hand calculations Hint: consider the relationship between the particles for certain values. Proton Kinetic \begin{tabular}{rcc} Energy(MeV) & 2 & F() \\ \hline 0.01 & 0.000021 & 2.179 \\ 0.02 & 0.000043 & 3.775 \\ 0.04 & 0.000085 & 4.468 \\ 0.06 & 0.000128 & 4.873 \\ 0.08 & 0.000171 & 5.161 \\ 0.10 & 0.000213 & 5.384 \\ 0.20 & 0.000426 & 6.077 \\ 0.40 & 0.000852 & 6.771 \\ 0.60 & 0.001278 & 7.173 \\ 0.80 & 0.001703 & 7.462 \\ 1.00 & 0.002129 & 7.685 \\ 2.00 & 0.004252 & 8.376 \\ 4.00 & 0.008476 & 9.066 \\ 6.00 & 0.01267 & 9.469 \\ 8.00 & 0.01685 & 9.753 \\ 10.00 & 0.02099 & 9.972 \\ 20.00 & 0.04133 & 10.65 \\ 40.00 & 0.08014 & 11.32 \\ 60.00 & 0.1166 & 11.70 \\ 80.00 & 0.1510 & 11.96 \\ 100.0 & 0.1834 & 12.16 \\ 200.0 & 0.3205 & 12.77 \\ 400.0 & 0.5086 & 13.36 \\ 600.0 & 0.6281 & 13.73 \\ 800.0 & 0.7088 & 14.02 \\ 1000. & 0.7658 & 14.26 \\ \hline \end{tabular}