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Calculate the three lowest energy levels in eV for an electron conned in an innite well of length a = 1.00 x 10' 10 In
Calculate the three lowest energy levels in eV for an electron conned in an innite well of length a = 1.00 x 10' 10 In (about the diameter of a hydrogen atom in its ground state.) Answer: E1 = 37.7 6V, E2 = 151 6V, E3 = 339 6V If a photon were emitted when the electron jumps from then = 2 state to the n = 1 state, what would its wavelength be? Answer: 1.10 x 105= m If the electron is in the ground state, what is the probability to find it betweenX = 0 and X = 3 /4? Answer: 0 .09 1 If the electron is in the ground state, what is the probability to find it between X = a/4 and X = a? (Do you need to perform a calculation@ Answer: 0.909
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