Calculate the value of the equilibrium constant, $K_c,$ for the reaction

$Q(g)+x(g)2M(g)+N(g)$

given that

$M(g)Z(g)$

$K_{cl}=3\mathrm{.}01$

$6R(g)2N(g)+4Z(g)$

$K_{c2}=0\mathrm{.}433$

$3x(g)+3Q(g)9R(g)$

$K_{c3}=12\mathrm{.}5$

$K_c=$