Calculate volume of cascade consisting of two ideal tank reactors required for the production of $50$M$($g$)/()$ day ethyl acetate. The reaction is described by the equation: C$\_(2)$H$\_(5)$OH$+$CH$\_(3)($C$)/($O$)$O H$=$CH$\_(3)($C$)/($O$)$O C$\_(2)$H$\_(5)+$H$\_(2)$O A$+$B$=$C$+$D Reaction rate in the liquid phase is defined by the expression: r$=$k$($c$\_($A$)$c$\_($B$)-($c$\_($C$)$c$\_($D$))/($K$\_($C$)))$ Reaction rate constant equals k$=7\mathrm{.}93*10^(-6)[($m$^(3))/($kmol$*$s$)]$ and the equilibrium constant equals K$\_($C$)=2\mathrm{.}93.$ The raw material is as follows $(\%$ mass$)$: u$\_($A$0)=46\%,$u$\_($B$0)=23\%,$u$\_($D$0)=31\%.$ The reaction should be carried out to $\backslash$alpha $\_($B$)=0\mathrm{.}35.$ Density of the mixture equals $1020$k$($g$)/($m$^(3)).$ Volumes of both reactors are the same.