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calculus (1 point) Substitution in the Indefinite Integral Part 1. Using the substitution: u = x - 8. Re-write the indefinite integral then evalu -4x(28

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(1 point) Substitution in the Indefinite Integral Part 1. Using the substitution: u = x - 8. Re-write the indefinite integral then evalu -4x(28 - 8) do = 0-0 Note: answer should be in terms of u only Part 2. Back substituting in the antiderivative you found in Part 1. above we have

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