Calculus 3 Final answers only is okay

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\fSection 12.2: Problem 10 (1 point) Evaluate the integral by reversing the order of integration. 2 dady = by\fSection 12.2: Problem 3 (1 point) Suppose R is the shaded region in the figure, and f(x, y) is a continuous function on R. Find the limits of integration for the following iterated integrals. 4 3 A= 1 B= C= D= -1 .H (b) f(z, y) dA = f(z,y) dady -2 R -3 E= F= -4 -4 -3 -2 -1 2 H=Section 12.2: Problem 4 {1 point} Find the volume of the solid bounded by the planes 3 = l}, y = (1,2: = l]. and m + y + z = 4. C] Section 12.2: Problem 5 {1 point} 1 3 Consider the integral f f f{z,y]dydz_ Sketch the region of integration and change the order of integraijon. o 3: Section 12.2: Problem 6 {1 point} 5'1 WE Consider the integral f f z, y}dyda3. Sketch the region of integration and change the order of integration. {1 o Section 12.2: Problem 7 (1 point) Consider the integral V9 y f(x, y) dxdy. If we change the order of integration we obtain the sum of two integrals: f(x, y)dydx + f(x, y) dydr a Jga (I) b 91(x) = 92(x) = C = d 93(x) = 94(x) =Section 12.2: Problem 8 (1 point) Consider the integral / f(x, y) dydx. Sketch the region of integration and change the order of integration. b pga(y) f(x, y)dxdy gi (y) a = b = 91 (y) = 92(y) =Section 12.2: Problem 9 (1 point) In evaluating a double integral over a region D, a sum of iterated integrals was obtained as follows: , f(z,u)as = [. J. s(z,y) dedy + f(z,y) dady. Sketch the region D and express the double integral as an iterated integral with reversed order of integration. f(x, y) dydx a = b 91 (x) = 92(I) =