Calculus Based Physics 2 Problem 2

(179%) Problem 2: Four different configurations show charge distributions and closed Gaussian surfaces. Assume that the surface normals are directed outward for each closed surface. If a charge appears to be located 92 + within a Gaussian surface, then it is, as opposed to being in the foreground or the background. The charges have the following values: 95 41 = -21.1 nC (a) (b) 42 = +27.2 nC 43 = +3.68 nC 94 = -2.79 nC 45 = +4.85 nC + End cap of area + + 4.0 * 104 m2 + + + + ++ + + Conductor a 91 + + + 6 = 2.0 x 10-6 C/m2 (c) (d) on25% Part (a) What is the total electric flux, in newton squared meters per coulomb, through the closed surface shown in drawing (a) of the figure? Grade Summary D = N . m3/C Deductions 096 Potential 1009% sin() cost tan() 7 9 HOME Submissions Attempts remaining 10 cotan( ) asin( acos() F 5 (096 per attempt) atan() acotan() sinh() 1 2 3 detailed view cosh( tanh() cotanh() + END O Degree: O Radians BACKSPACE CLEAR Submit Hint Feedback I give up! Hints: Feedback: & 25% Part (b) What is the total electric flux, in newton squared meters per coulomb, through the closed surface shown in drawing (b) of the figure? &25% Part (c) What is the total electric flux, in newton squared meters per coulomb, through the closed surface shown in drawing (c) of the figure? & 25% Part (d) Drawing (d) of the figure shows a portion of an infinite conducting plane viewed edge-on. The Gaussian surface is a "Gaussian pillbox" whose sides are perpendicular to the infinite plane, but the end cap, with an area of 4.0 x 10 4 m, is parallel to the plane. The conductor has a charge per unit area of = 2.0 /C/m2. What is the total electric flux, in newton squared meters per coulomb, through the Gaussian surface