Calculus Test Question

2. A curve is defined by the equation 4x2 - 3y2 = *. Determine the value of " at the point (1,1). [3 marks] 4x 2 - Bye- i cy ( 1 , 1 ) dx 3. Consider the function f(x) = 2xv2 - x2 on the interval [-1/2, v2]. Determine the absolute maximum value and the absolute minimum value of f (x) over this interval. [4 marks] S(x):2x52-x2 OK - 112, 52