Can give a more clearer explanation on this question in part (a) why outlet stream of water is 0.100kg H2O/kg? (b) the qn mention if fresh feed is 20 000kg/h why use 100kg/h? I do not understand

1.3 A fresh feed of seawater containing 3.5 wt% salt passes through a series of 10 evaporators. Each evaporator vaporizes the same amount of pure water. The vaporized pure water streams are then condensed and combined to obtain a single product water stream. The seawater at the outlet of the tenth evaporator contains 5.0 wt% salt. (a) Draw a fully labelled process flow diagram showing the first, fourth, and tenth evaporators. Indicate clearly all information related to the streams. (5 marks) (b) If the fresh feed of seawater is 20,000 kg/h, calculate the fractional yield of combined pure water from the process (kg total H2O recovered / kg H2O in fresh feed). (10 marks) (c) Calculate the weight percent of salt in the solution leaving the fourth evaporator