Can someone answer these 5 questions??? they have been answered but they are WRONG. I need someone to redo it as per what my teacher wants!!!

1 of 8 Physics 20: Mrs. Tyler Assignment 7 22 142 Assignment 7 Unit B Module 1, Lesson 4: Free-Body Diagrams and Net Force Lesson 1 of this assignment is worth 9 marks. The value of each question is noted in the left margin in parentheses. Remember: all net force problems should include a free-body diagram. 1. Beta convinces Alpha to drag their ice-fishing shack to a new location by pulling it with ropes. Alpha applies a force of 150 N [175 ] on one rope and Beta applies a force of 175 N [190 ] on another rope. What is the net force applied to the shack by Alpha and Beta? Assume the ice is frictionless. Show all work. (6) Alpha force : 2/6 sin ( 1750 ) = app your = sin (175" ) XISON app : - 11.5 N ( negative because it's in the opposite direction to positive x-axis ) X cos ( 1750 ) = ads / hyp Start by drawing your free body diagram adj = cos (175' ) , 150N and resolving vector diagram. adj = - 138. IN ( negative as it's app . to positus younis ) Alpha : horizontal veshawl 71.5 & - 135. 7N I see you have tried to find resolving vectors here but your calculations are sin ( 190 0 ) = app / hyp incorrect. You are also missing the final steps. " pp = sin ( 190 " ) * 175x See Lesson 4, P6, SC7 "Free-Body Cop = - 104- 3 N Diagrams in 2D" X cas ( 190 ) = adj / nyp adj = cos ( 190 - ) * 17SN adj = 170- 9 N X Bels horizonta + verbal is -loy. 3N @ ADLC All Rights reserved ( 2019 ) and 170. 5 N2 of 8 N Physics 20: Mrs. Tyler Assignment 7 2. The next day, Alpha decides to move the shack back to its original location. Alpha (having had a nutritious breakfast) is able to pull the 1800 kg shack at a constant velocity with a force of 190 N. Calculate the coefficient of friction between the shack and the ice. Show all work. 2.5 (3) applied fora = 190 normal force = 180kg x 9. 8 lm / s mass = 1800 kg = 17, 658 N gravity = 9.81 m/ s 2 coefficient of Frichin = 190N / 17, 658N =0.0108 Please show free body diagram and direction for full marks. See Lesson 4, P5 "Free-Body Diagrams and Net Force" After you have completed all questions in Lesson 4, please place your assignment in a safe place until you have finished Lesson 5. Unit B Module 1, Lesson 5: Solving Net Force Problems Lesson 2 of this assignment is worth 33 marks. The value of each question is noted in the left margin in parentheses. Remember: all net force problems should include a free-body diagram. 3. A textbook with a mass of 2.18 kg is pulled across a table with a horizontal force of 5.5 N [E]. If the table has a coefficient of friction of 0.15, what is the acceleration of the textbook? (2) mass = 2. 18kg applies force = 5.5 N (E] 1.5/2 coefficient of fricken = 0.15 granny - 5.8lm/s normal face= 2.18kg4 9.81 mls - 21. 37N force of frichu = 0.15+ 21.37N = 3. 2IN For full marks you need to show direction, as well as a 5. SN[E] - 321 0 FBD and indicate direction in your answer. = 2. 29 N CEJ a = 2. 2 AN CC] / 2.18 kg G = 1. 05301 5rim PLC All Rights Reserved (2019)4. Use the following information to answer parts a and b. A 10.0 kg toboggan slides down a frictionless icy hill with a slope of 250. a) Calculate the parallel component of the toboggan's weight. (Ms: : \"\"9\"? O Show, cit{u 1: 93.0 \\ '2. Please show the free body diagram O.5\\ i' 5'' c' Mb This would be negative direction. ism, msws' :'I-s. W > 9 Qt .\\ N xs'mL'15- =aman b) Calculate the acceleration of the toboggan. 0.75/1 Sch 3M \"0.6% See Lesson 5, P6 \"More on Incline Planes\" Fnetzmax =- 3 -Q'3m[a' negative direction 5. Use the following information to answer parts a and b. A 7.5 kg crate is placed on a ramp that is at an angle of 30.00 relative to the horizontal. a) What is the force of friction required for the crate to remain stationary? mass -: 7.5"? Please review how to properly complete these assignments I f M 30 -0 awed to see the vector diagram, as well as the formula E} 5 5 n this? you are using. The answer must be rounded to proper sig digs. There is a summary in the course introduction that will help. '7. 5b,, y (ism/fur sac-909') : 363M