Can someone answer this please?

1) Refer to the circuit diagrams made in Researcher 1 and 2, explain why the Researcher 2) Refer to the DA sketches that compare the voltage of the bulb with the voltage of the 1 circuit results in the Oscope measuring the voltage of the bulb, while the Researcher 2 capacitor. Why does the bulb behave in the way that you observed through this lab? Why does it circuit results in the Oscope measuring the voltage of the capacitor. give weak flashes when you tap the switch quickly, but strong flashes when you slowly push the switch? esearchers: Oman OF Switers pressed DA 3: "for base to be steady . 5sec Oscope probe steady state vantage to capacitor graph measure voltage . Voltage across the light where bulo is on Steady Stake V. = 0 bulb to ground. Time Volts when switch is pressed ground DAZ capacit is Pull . Oscope probe measure voltage across the capasitor Graph or switch release = ground to ground . When Switch is Voltage ( time It takes released switch is released to reach Stendy Time (5 ) ab+ 5 sec Voltage Switch is released Steady State Time app resimas needed for s 3 ) You might have noticed that in the DA sketches there is a derivative relationship between the two graphed functions f (t ) x - F (t ). Identify whether f (t) is the voltage of the capacitor or the voltage of the bulb. Similarly, identify whether F(t) is the voltage of the capacitor or the voltage of the bulb. Explain how you made this identification. (If you would like the above relationship can also be written as f (t) = K-F(t) for some constant K.)