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Can someone answers these 3 questions ASAP??? I've tried these questions before, and got it incorrect/ partial marks, I've shown the original question and what

Can someone answers these 3 questions ASAP??? I've tried these questions before, and got it incorrect/ partial marks, I've shown the original question and what response she had gave, can you redo the questions accordingly??? TYSM

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3. A Canada goose flew 1.45 km [15.0" S of W] to feed, then it flew 1.64 km [70.0\" S of E] to its roosting location. Determine the goose's displacement, using the graphical/tip-to-tail method of vector addition. Answer to two significant digits. Seal-e. '. T - Physics 20: Mrs. Tyler Assignment 3 5 c) Using your results from a and b, determine the components of the resultant vector. (2) V . => resultant vector VRu = Vix " V2 =- 65. 38 + 98. 29 = 32. 918M/S (32. 9 MB "Ry : viy + vzy : - 37.75- 68.82: - 106.57 m(s ( 10 7 ~ Is ) d) Draw a rough sketch the resultant vector using the components found in part c. (1) e) Calculate the resultant magnitude using your sketch from part d. (1) f) Calculate the resultant direction using your sketch from part d. Use polar-positive notation. (2 ) Zon b = VRY - - 106.04 VRU 32. 92 O = ten -' ( - 106.04 - - 72.75 " 32992 Polar Positive Notation = 0 = 360' - 72.75' - 287.25 ADLC All Rights Reserved (2019) - 28702 Physics 20: Mrs. Tyler Assignment 3 2 3. A Canada goose flew 1.45 km [15.0' S of W] to feed, then it flew 1.64 km [70.0' S of to its roosting location. Determine the goose's displacement, using the graphical/tip-to-tail method of vector addition. Answer to two significant digits. Canada Goose Flying Scale (5) lom = 1km 2/5 2 3 9 5 6 7 8 9 10 5 E 145km 1: 646m / 2.3 km 5 displacement = A2 + 32 + QAB Cose See Lesson 1, P3 "More on the Tip to Tail Method" and watch "Adding Vectors Graphically" video V1.45? + 1.642+ 1.45x 1.64 + Cos 850 I would suggest changing the scale so you can measure this easily. Remember you also need to measure the angle 2.281 km of your resultant vector. displacement = 2.3 km X ADLC All Rights Reserved (2019)2y d) Draw a rough sketch the resultant vector using the components found in part c. (1) 0.75 VQ : 32.92 mls We should only see one resultant vector here. e) Calculate the resultant magnitude using your sketch from part d. (1) Resultant = ]VR / = Rx + VR. = (32. 12) 2 + ( 106.04 )2 111. 03 mls8. Your flight to your friend's house in Halifax has a short layover in Toronto. Your total flight time is 6.25 hours. The first flight to Toronto covers a distance of 2700 km [35.0' S of E], and the second flight to Halifax covers a distance of 1280 km [10.0 N of E]. (1) a) What was the total distance you traveled? Show all work. di = 2700 km ( 35 0 Soft 12 = 1280 km (lo'N of E ) Total distance - ditde = ( 270+ 1280 ) km = 3980 km\f8. Your flight to your friend's house in Halifax has a short layover in Toronto. Your total flight time is 6.25 hours. The first flight to Toronto covers a distance of 2700 km [35.0' S of E], and the second flight to Halifax covers a distance of 1280 km [10.0 N of E]. (1) a) What was the total distance you traveled? Show all work. di = 270 km ( 350 Sof ) 12 = 1280 km (lo'N of E ) Total distance : dirde = ( 270 + 1280 ) km = 3980 km ADLC All Rights Reserved (2019)b) What was your displacement? Show all necessary work. (9) N 4 W G 35 Both of these should be drawn from the origin as two separate vectors S X di = 270 ( (as as ; - sin 35 . ] Each vector needs to be calculated = (2all. 71- 1548. 66 ; ) km separately d2 = 1280 ( cos 10 ( it sin 10. 3 ) km x = (1260. 55+ 222. 27 ] ) km d = d, + d2 = (3472. 261 - 1326.393 ) 1d ) = d,2+62 = 3716 . 97 km ton D = 1326.39 = 0. 382 3472.26 0 = 20. 91 " S OfE

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