Can someone check this for me. I'm not sure if they're all right.

signment: Use the Product Rule to differentiate the function. ( cox + 5 ) ( 3 x 2 ) + ( x 3 - 2 ) ( 6 ) 18 x 3 + 15 x 2 + 6 x 3 - 12 1. 9 (x ) = (x2 + 1) (x2 - 2x) - 14 x 3- 6x2+2x- 2 2 . f ( x ) = ( 6 * + 5 ) ( x 3 - 2 ) ( x 2 + 1 ) ( 2 * - 2 ) + ( x 2 - 2 x ) (2 x ) 24 x 3 + 15x 2- 12 2x - 2x2+2 x - 2 + 2x 3 - 4 x2 3. h ( t ) = Vt ( 12 + 4 )1 7+ 2+ 4 4 (+ 3 ) ( +2 + 4 ) 3+ 3 4. 9 ( x ) = x( 4 -x2) ( xy( x) 4 x2 - X ( + 5 ) ( 2 + ) + ( + 2 + 4 ) 1 5 + - 3 NOW 2+ 3 + 3 + 3 + 4+ WIN 2 x 2 _ zx 14 5 . f ( x ) = x ' Cos x 2 - 5 x + ov/ + 6. g (x) = Vx sinx ( x ? ) ( ces x ) 3+ 20 X ( x 2 ) ( sinx ) ( x 3 ) ( - sink ) + ( cos * ) ( 3 x 2 ) (x= ) ( cosx) + (sinx) ( zx z) - X sinx + 3 x 2 cos x VX cosx + sin x 7. For f( x) = (x3 -3x) (2x2 + 3x +5), find f'(0). 8. For f ( x ) = ( x2 - 2x + 1) (x= = 1), findf'(t ). ( x 3 - 3 x ) ( 4 * + 3 ) + ( 2 x 2+3 *+5 1 1 3 x2-3) ( x 2 - 2 * + 1 ) ( 3 x 2 ) + (x - 1) / 2 x 4 x4 + 3 x 3-12x2-9x+ 6x4+ 9x3+15 x2-4x2-4x-15, 4 -3 x - 6 * 3 + 3 x 2 + 2x4- 2x3 10 x7+ 12 x3 - 3x2 - 18x - 15 5 x 4 - 8 x3 + 3 x2 - 2x + f (0 ) = 1- 15 5- 8+ 3-2+3 fill1 = 10 ) 9. For f (x) = xcos x , find f' 10. For f (x) = x2 sin x, find f' (7). f'lx ) = x 2cos * + sin x (2k) (x)kos x ) f ' ( # ) = 4 (' ( x ) = x 2 cosx + 2 x sink ( x ) ( - sin x ) + ( cosx PIlIT ) = IT 2 COSTT + 2 PPS 10 X - sinx + cosx f' ( IT ) = - 1 2 1 1 - sin y + cos IT_ V2 / VZ