Can someone explain the breakdown of the answer? It says construct a Schild plot but most answers I've seen do not have a Schild plot attached and it's confusing how these values are derived

8. Determine the pAz for mepyramine. [6]. First, pick the most appropriate agonist. Use at least 3 doses (concentrations) of antagonist and try to limit yourself to 8 doses of agonist each. Table all data. No need to plot all d-r curves, just read the relevant data from the screen-plots [9] Construct a Schild Plot and determine the pAz. Show all the calculations. The ECso is equal to 2.0 x 10" excluding the mepyramine. Log10 EC50 = -6.7 Mepyramine 1 x 10-8 1 x 10-7 1 x 10-6 concentrations Log 10 EC50 -5.7 -4.7 -3.7 EC50 10-57 = 2.0x 10-6 10-47 = 2.0x 10-5 10-37 = 2.0x 104 Log10 (dose ratio) -5.7 - (-6.7) = 1 -4.7 - (-6.7) = 2 -3.7 - (-6.7) = 3 Dose ratio 2.0 x 10 A (-6 2.0 x 10 A (-5 2.0 x 10 A (-4) 2.0 x 10 A (-7) 2.0 x 10 A (-7) 2.0 x 10 A(-7) 10 100 1000 Log 10 (dose ratio - 2 3 1) The pA2 is the X-intercept. The value of the X-intercept is obtained at the point where y = 0. Using the formulae below; Log10 (dose ratio - 1) = log10A + pA2 Log10 (dose ratio - 1) = Log10 (2 - 1) = 0 Therefore, -log10A = pA2 Considering that pA2 is -9.0 from the Schild plot -log10A = -9.0, hence; 10-90 = 1 x 10-9