Can someone explain to my the highlighted part? Why is that the case?

EXAMPLE 3 Let V = (2, 0, 0) and W = (0, 1, 1). Determine u = v X W using the geometric properties of the cross product rather than Eq. (3). Solution We use Theorem 1. First, by property (i), u = V X W is orthogonal to V and W. Since V lies along the T-axis, u must lie in the yz-plane (Figure 4). In other words, u = (0, b, C). But u is also orthogonal to W = (0, 1, 1), so u . w=b+c= 0 and thus u = (0, b,-b)