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Can someone help me with B and C (5%) Problem 14: Resistivity in metals increases with temperature according to the equation pm = .00 [1
Can someone help me with B and C
(5%) Problem 14: Resistivity in metals increases with temperature according to the equation pm = .00 [1 + \"(T T0)] where a is the temperature coefcient of resistivity, and p0 is the resistivity at reference temperature To . For a particular wire, the temperature coefcient of resistivity is a = 4.58 X 103 'C1 , and the resistivity is p0 = 7.01 X 107 S2 - m at the reference temperature To = 267C. 33% Part (2:) Input an expression for the temperature, T2 , at which the resistance of a particular wire will be twice as high as at is at the reference temperature, Tot (Both temperatures are in degrees Celsius .) V Correct! T2 =T0+1/(1 88 33% Part (b) What is this temperature, in degrees Celsius, for the wire described in the problem statement? T2 = 280.7 'C $8 33% Part (c) If the wire has a length of 1.00 m and it has a circular cross section with a radius of 1.00 cm, what is its resistance, in ohms, at a temperature which is twice the reference temperature, T = 2T0? (Note that the temperature is doubled, as opposed to the resistivity.) R: 52 Grade Summary Deductions Potential 100%Step by Step Solution
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