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Can someone help me with the answers and explanation for this question please? Thank you Variance estimation is an usual interest of statisticans. It helps

Can someone help me with the answers and explanation for this question please? Thank you

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Variance estimation is an usual interest of statisticans. It helps to construct confidence in- tervals for estimations. An estimator for variance o' could be the sample variance S,. mi EL,(Y: - Y)? where Y = 1 ELY. It is known that the random variable ("-1)s has the x2 1 distribution with degree of freedom n - 1 if Y1, ..., Y, are independent and identi- cally distributed with the Normal(/, ?) distribution. That is also to say the random variable ("-1)s- has the Gamma(,], ;) distribution. We will start from Normal approximation to Gamma using the CLT. Let X1, ..., Xn are independent and identically distributed with the Gamma(a, 8) distribution. Then we have X = 1ELIXQ, #x = E[X] = g and of = Var(X) = 14 no. We could approximate the probability P(X y) = with a = 6, 8 = 3 and n = 40 (Give your answer up to 4 decimal places). QUESTION 10 : Take n = 40 and o? = 1. Using the CLT, approximate the quantile c, that the probability P(S, c2) = 0.025. (Give your answer up to 4 decimal places)

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