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can someone help me with the last question C and D please not sure how to do them VIRTUAL LABORATORY ASSIGNMENT: LINEAR KINEMATICS Purpose: In
can someone help me with the last question C and D please not sure how to do them
VIRTUAL LABORATORY ASSIGNMENT: LINEAR KINEMATICS Purpose: In this virtual assignment: (1) We will examine a displacement v. time graph and a velocity v. time graph for a situation of motion with constant acceleration. (2) We will simulate relative velocity in one dimension. Procedure: Part 1: Displacement v. Time and Velocity v. Time graphs A car is initially at rest. It then accelerates at 2 m/s'. Using the appropriate equations, a. Create a graph of displacement v. time. Fill out the following table and use it as a guide: Time (s) 0 1 2 3 4 5 6 7 8 Position 16 25 36 49 64 (m) b. Create a graph of velocity v. time. Fill out the following table and use it as a guide: Time (s) 0 1 2 3 4 5 6 7 8 Velocity O 2 G 10 12 14 16 (m/s) a=m/ X = Vat+ Jatz * = 1(2 m/52)-+ 2 * = latz. *# b ) V= Vit at V= 0 + at V = at V= ( Im/s ")t\fC. Velocity as the derivative of displacement with respect to time: Pick 4 points along the displacement v. time graph that are roughly evenly spaced and construct tangent lines to the curve of x vs. t at each of these points. Draw a slope triangle for each tangent line, and measure the slopes to determine the velocities at these 4 times (Remember, instantaneous velocity is the slope of the x vs. t graph). Be sure to make the base of your slope triangles at least 0.20 s long. Compare these four slopes with the four corresponding values of the velocity from the vvs t graph, evaluated at the tangent points (aka times) you chose. Use the table below to summarize your results and discuss your findings. Time (s) Slope of tangent line from x Velocity from v vs. t graph vs. t graph (m/s) 2 4 4 4 6 12 19 16 16 d. Displacement as the integral of velocity over time: Show that the area under the velocity graph for a selected time interval is equal to the change in displacement during the same time interval. Choose a time interval of about 0.5sStep by Step Solution
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