can someone help me with the simple algebra of solving this equation? I can not remember how to divide fractions to save my life.

- A solution of 0.50g hyoscyamine in 150mL water is to be extracted into 3 extractions of 50mL diethyl ether. How much hyoscyamine would be extracted into the diethyl ether layer in this process? - To solve this problem examine the definition of K K=Solubilityinwater(mLg)solubilityinorganic(mLg) - The amount of hyoscyamine that will partition into diethyl ether is (x) and the amount that will partition into the water is (0.50gx) 4.07=(150mLwater0.50gx)(50mLdiethyletherx)=0.29grams - This result means that 0.29g is extracted into the dicthyl ether in the first extraction and 0.21g remains (n the aqueous layer (0.50g0.29g)