Can someone help:

We will need to imagine the surfaces of the spheres. Since the spheres have a radius of 0.30 m the surface will lie 0.30 m from the centre of Q B. Record the potential at the surface of QB: VB = -57.7 V. Your last answer was interpreted as follows: -57.7 Now take a set of measurements at different intervals along the line connecting the two spheres. Remember to not go too close to the positive charge because then you would be inside the positive sphere. Choose r = 0 as the surface of sphere Q B. i.e. position r = 0.20 m is 0.50 m from the centre of Q B- Position (m) Potential (V) 0.2 -31.7 0.5 -17.7 1.0 -9.0 1.8 -2.4 2.7 3.0 3.5 10.3 3.9 18.1 4.2 31.9 4.4 (the surface of sphere A) 57.1 Now assume that there is a 5% uncertainty in the measurements for the potential (including that of VB), and then set the potential of the negative sphere to 0 V. Calculate the new potentials at the measured positions with their absolute uncertainties. Position (m) Potential (V) Uncertainty V 0.2 26.0 0.5 40.0 1.0 48.7 1.8 55.3 2.7 60.7 3.5 68.0 3.9 75.8 + 4.2 89.6 4.4 (the surface of sphere A) |114.8