Question
Can someone please help answer these question are due today 4/18/18 @ 9pm please. Chapter 6, Section 3-CI, Exercise 141 Your answer is partially correct.Try
Your answer is partially correct.Try again.Use the normal distribution to find a confidence interval for a difference in proportions p1-p2 given the relevant sample results. Assume the results come from random samples.
A 99% confidence interval for p1-p2 given counts of 33 yes out of 100 sampled for Group 1 and 21 yes out 140 sampled for Group 2
Give the best estimate for p1-p2 , the margin of error, and the confidence interval.
Round your answers to three decimal places.
Best estimate :
Margin of error :
Confidence interval : to
Chapter 6, Section 1-CI, Exercise 030
Your answer is partially correct.Try again.Standard Error from a Formula and a Bootstrap Distribution
Use StatKey or other technology to generate a bootstrap distribution of sample proportions and find the standard error for that distribution. Compare the result to the standard error given by the Central Limit Theorem, using the sample proportion as an estimate of the population proportion p .
Proportion of lie detector trials in which the technology misses a lie, with n=47 and p^=0.359
Click here to access StatKey.
Round your answer for the bootstrap SE to two decimal places, and your answer for the formula SE to three decimal places.
Bootstrap SE=
Formula SE=
Chapter 6, Section 1-HT, Exercise 048
Incorrect.Use the normal distribution and the given sample results to complete the test of the given hypotheses. Assume the results come from a random sample and use a 5% significance level.
Test H0:p=0.25 vs Ha:p<0.25 using the sample results p^=0.16 with n=100
Round your answer for the test statistic to two decimal places, and your answer for the p -value to three decimal places.
test statistic =
p -value =
Conclusion:
Chapter 6, Section 3-CI, Exercise 154
Survival in the ICU and Infection
In the dataset ICUAdmissions, the variable Status indicates whether the ICU (Intensive Care Unit) patient lived (0 ) or died (1 ), while the variable Infection indicates whether the patient had an infection (1 for yes, 0 for no) at the time of admission to the ICU.
Use technology to find a 95% confidence interval for the difference in the proportion who die between those with an infection and those without. (pI-pN)
Click here for the dataset associated with this question.
Round your answers to three decimal places.
Confidence interval :
to
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