Can someone PLEASE help me answer these questions down below on the bottom. I am not sure how to answer these. I would appreciate if someone can help me from the data I have produced please.

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Data:

Use the data collected to compute the table below. Triangle cos(C) (a' + b2 - c?) % Difference 2ab Error -0.1391 -0.335 -82.658% 0.03 0.347 163.54% 48 For at least the first row above, show all of your work in typed format. difference * 100 %difference error = average Difference = [cos(C) - the +2 for triangle 1 diff = |-0.1391 - (-0.335)| = 0.1959 for triangle21 diff = 10.0348 - (0.347)| = 0.3122 Average = [cos(C) + 2+83+21/2 for triangle 1 avg= (-0.1391-0.335)/2 = -0.237 for triangle 2 avg = (0.0348 + 0.347)/2 = 0.1909 % difference error: difference * 100 %difference error = average for triangle 1 = ((0.1959)/(-0.237))*100 = -82.658% for triangle 2 = ((0.3122)/(0.1909))*100 = 163.54% The % percent error = (difference/average) * 100. Difference = |cos (C) - (@-+b2-3) 2ab Average = (cos(C+) (@+b- -5)/2 In principle, one could apply the law of Cosines to calculate cos(A) and cos(B). 5. Verify the Law of Tangents Use the Data collected in Table 0 above to complete the Table below Triangle Tant % Difference Error Tan(A + 3, 1 -0.027 -0.705 -185.24 0.429 0.315 36.645. Verify the Law of Tangents Use the Data collected in Table 0 above to complete the Table below Triangle (a -b) (a + bj TantZ % Difference Error Tan A+ B -0.027 -0.705 -185.24 2 0.429 0.315 36.64 For at least the first row above, show all of your work in typed format. Triangle 1: Difference: ab tan ( A,#) a+5 Lan( AtBj | = | - 0.027 - (-0.705) | = 0.678 Average: tan( au ath tan AtB; 0.732 = 0.366 2 2 % Error: difference Average x 100 = 185.24% Triangle 1: Difference: ton ( 4-8) atb ton ( 410 = 0.429 - 0.315) = 0.114 Average: tom ( 4-B ) tan ATH = 2 0.744 = 0.372 2 % Error: difference x 100 = 36.64% Average