Can someone please help me with this, I want it similar to the example down below. I want help with a summary and application related to the topic that's covered and I am a bit confused about what application I could talk about or use.

Thanks

Question:

Here is a summary of the main ideas in Chapter 17 1. There are two types of mechanical waves: Transverse and Longitudinal. Transverse waves are waves that required the medium to oscillate perpendicular to the direction of the wave. If the wave is moving to the right, transverse waves will move the medium up and down, perpendicular to the wave motion. Longitudinal waves move the medium in the direction of the waves - back and forth 2. Sound waves are longitudinal mechanical waves where the medium (the gas density) oscillates back and forth in the direction of the wave motion. The velocity of a sound wave is: V = B where B is the bulk p modulus of the medium given by the equation B = _ AP 41 which is the negative of the medium's change in pressure for the fractional change in the volume and pis the density of the medium. 3. In a longitudinal wave, the displacement s(x,t) of the medium can be described by a sinusoidal function (cosine chosen in this chapter) and written as s(x, t) = Sm cos(kx - wt). This shows that the medium moves back and forth with the amplitude given bySm. This creates regions of high pressure and low pressure (compression and rarefaction). The pressure change can itself by described by a sinusoidal function which is out of phase with the displacement. In this case, the pressure change in the wave can ge written as: Ap(x, t) = 4pm sin(kx - wt) where Apm is the pressure variation in the wave 4. The interference of two sound waves traveling in the same direction can be described by the principle of superposition just as we did in Chapter 16. The superposition of two sound waves of equal amplitude and frequency is S'm (2, t) = 2sm cos( 24) cos (kx - wt + 24) where up is the phase difference of the waves at the point x. This shows that the superposition of two waves is a maximum which occurs cos (4) = 1 or 4 = 2 T m where m is an integer m=0, 1,2, . ... Similarly, the waves will completely cancel when cos ( 4) = 0 ory = (2m + 1)n m = 0, 1,2,3. . . 5. The phase difference can be described in terms of the path difference from each of the sources to the point of interference. When the path difference is an integral number of wavelengths, there will be constructive interference. This can be written as = = 0, 1, 2, 3, 4 . . . Similarly when the path difference is equal to odd multiples of the wavelength, the waves will experience destructive interference AL -. 5, 1. 5, 2.5, . . . 6. Suppose a sound source is transmitting sound with power PS. As this sound travels outward from the source, the intensity I at a point from the source is given by I = -. If the area is that of a sphere of radius r, then the area can be written as A = 4mr2 and the intensity 1 = 1 2 . This shows that the intensity of an isotropic source falls off7. Because of the wide range of intensity levels that can be heard by the human ear, it is useful to describe these with a logarithmic scale. We describe the sound level in decibels by the following equation: B = 10 log10 (To where I is the intensity in Watts per square meter described previously and To is the standard reference intensity threshold equal to 10-12 W/m2 8. Standing waves can be set up in pipes if a proper transmitted frequency is introduced. If the pipe is open at both ends, a standing wave will be set up if f = 27 n = 1, 2, 3, 4, 5. If the pipe is one at one end, the frequency can be written as f = # n = 1, 3, 5. The integer n is called that harmonic number. Most musical instruments can be modeled as an open-open pipe, an open-closed pipe, or a string fixed at both ends. 9. When two sources emit frequencies not exactly the same, one can discern an interference effect based on the difference in their frequencies. This difference in their frequency is called the beat frequency. 10. The Doppler effect is the change in the observed frequency if the source or observer (detector) is moving relative to the source. If the source is stationary and the detector moves toward it (or away from it) with speed Ud. The frequency observed by the detector is given by f' = f vtud v where v is the velocity of sound, and the + in the indicates the receiver moving toward the source. The sound frequency at the receive shifts to higher frequencies, but the observed wavelength remains the same. If the receiver is fixed and the source moves toward it with speed Us, the observed frequency also increases and is given by J ( Utvs ) In this case, the '- sine is used to describe a source moving toward the receiver and the '+' used when it moving away. In this case, the observed wavelength will be changed. When a source moves toward a stationary receiver at the speed of the sound in the medium, the observed frequency approached infinity. 11. The Mach cone angle is the ratio of the speed of sound in the medium to the speed of the source or sin 0 = ?,Question: Two small identical speakers are connected (in phase) to the same source. The speakers are 3.00 m apart and at ear level. An observer stands at X, 4.00 m in front of one speaker as shown. If the source emits a sound with a frequency of 610.0 Hz, what is the phase difference from the perspective of the observer? Summary: For this problem, we will be using the equation for wavelength, = 4, then we will calculate the path displacement, finally we will calculate the phase difference using the equation, ( = 4:2 X 2TT. Solution: Knowns: L1 = 3m L2 = 4m f = 610. 0 Hz v = 343 m/ s (Speed of Sound) Solution: L3 = VL12 + L22 = 5m to find the path displacement we will use L3 and L2, because those are the paths of each sound. Ax = L3 - L2 = 1m finally, we plug together all of our equations to calculate the phase change. ( = 4*27 = 127 = 4271 - 6102 343 271 = 11. 2rad Application: One way that sound waves are used in our daily lives are the headphones many people use. They are little speakers that have 4 main components; "a magnet to move back and forth, a wire coil around that magnet, a diaphragm that pushes air, and a suspension that holds the diaphragm". When these are designed, the specifics of the human ear and how it may distort the sound must be carefully considered.APm = (Up@)sm, Where Am = pressure variation amplitude, u = the speed of sound in air, p = density of air, @ = 2nf, where f is the frequency of the wave, and Sm = displacement amplitude. w = 2nf = 2x(330 Hz) = 660x Hz Sm = 14 pm = 14 x 10-6 m So, Apm = (340 m/s) (1.2 kg/m3) (660x Hz) (14 x 10-6 m) = 12 PaThe speed of sound in air is 340 m/s, and the density of air is 1.2 kg/m3. If the displacement amplitude of a 330-Hz sound wave is 14 um, what is its pressure-variation amplitude