can someone please help me with those questions

The bearing of a ship from a lighthouse was found to be N 15 E. After the ship sailed 5.8 miles due south, the new hearing was N 26 E. Find the distance between the ship and the lighthouse at each location. The ship began |:| miles from the lighthouse. (Simplify your answer. Type an integer or a decimal. Round to the nearest tenth if needed.) The ship nished at miles from the lighthouse. (Simplify your answer. Type an integer or a decimal. Round to the nearest tenth if needed.) The solution set for the equation cos 9 = - T is {135,225}. Use this information to solve the following equation over the interval [0,360). 0 5 cos=- 2 2 Select the correct choice below and, if necessary, ll in the answer box to complete your choice. a} A- The solution set is { }. (Simplify your answer. Type an exact answer, using 7: as needed. Use integers or fractions for any numbers in the expression. Use a comma to separate answers as needed. Do not include the degree symbol in your answer.) a: a B. The solution set is Q). Solve the equation in the interval [0,360). Use an algebraic method. 95in29-7sin9=1 Select the correct choice below and, if necessary, ll in the answer box to complete your choice. '3' A- The solution set is { }. (Simplify your answer. Round to the nearest tenth as needed. Use a comma to separate answers as needed. Do not include the degree symbol in your answer.) {:23 B. The solution is the empty set. Verify that the trigonometric equation is an identity. ( cot 2a + 1) (cot 2a -1) = csca-2csca . . . Which of the following statements establishes the identity? O A. ( cot2a + 1) (cot 2a-1) = tan ?a( sec 2a + 1) = tan 2a (tana + 1+ 1) = csc 4a-2csco O B. ( cot2a+ 1) (cot 2a-1) = cot 2a( csc 2a + 1) = cot 2a (cot 2a + 1 +1) = csc 4a-2csca O c. ( cot2a+ 1) (cot 2a-1) = csc 2a (cot 2a -1) = csca ( csc2a -1-1) = csc 4a-2csca O D. ( cot2a+ 1) (cot 2a-1) = sin 2a (1 + cosa) = sin 2a (1 + 1 - sina) = csca-2cscaSelect the correct choices that complete the sentence below. sin A sin B sin C An alternative form of the law of sines is C a b