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Can someone please solve this problem? (14%) Problem 5: A 3-D printer lays down a semicircular arc of positively charged plastic with a radius R

Can someone please solve this problem?

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(14%) Problem 5: A 3-D printer lays down a semicircular arc of positively charged plastic with a radius R = 3.4 cm, and a linear charge density of 1 = +1.6 uC/m. After the printer has finished the are, the de stylus moves to the center of the are as shown. The minute segment of the plastic are highlighted in the diagram subtends an angle do. Stylus tip R X theexpertta.com 14% Part (a) Input an expression for the charge dq on the segment of size do in terms of given parameters. dq = AR de Correct! 4 14% Part (b) Input an expression for the electric field vector, dE, generated at the center of the arc by the minute segment of plastic subtending the arc de. Express your answer in terms of given parameters, the Coulomb constant k, and the unit vectors i and j. 14% Part (c) Evaluate the expression from part (b) as an indefinite integral to determine the x-component of the electrical field, Ex, at the center of the arc generated by the entire line of charged plastic. Grade Summary Ex = Deductions 0% Potential 100% cos(0) sin(8) Submissions Attempts remaining: 10 A 5% per attempt) C detailed view m go NO Submit Hint I give up! Hints: 5% deduction per hint. Hints remaining: 2 Feedback: 0% deduction per feedback. 4 14% Part (d) Select the limits of integration that would result in the correct calculation of the electric field at the center of the are generated by the entire line of charged plastic as shown in the diagram. 4 14% Part (e) Use the limits from part (d) and the expression from part (c) to determine an expression for the magnitude of the electric field at the center of the are generated by the entire line of charged plastic. 4 14% Part (f) Calculate the magnitude of the electric field (in N/C) at the center of the are generated by the entire line of charged plastic. 4 14% Part (g) What direction is the electric field at the center of the arc

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