Can someone redo these questions?? I got them wrong but need them redone thx!!!

2. Your 1500 kg SUV enters a 35.0 m radius traffic circle. It is an icy day and the coefficient of static friction between your tire and the road is 0.15. What is the maximum speed that you can go through the traffic circle without sliding? Answer in km/h. Solve for max Velocity : (3) Fc = mu"lr velocing : V = V( for / m ) mulls : mus mig Max static FAizhar : mus xfn V 2 = musrg V = Vugr V = VCmus'S friction . V = V CaIS x 35. OM x 98/ m/5 2 ) = 6.644 normel . Fn = ms V = 6.644 m/s x 3. 6koch/m/s= 23. 9 km/ur face ffrichn = mus my4. Use the information below to answer parts ab. A ball is attached to a string and swung in a vertical circle at a constant speed. Assume air resistance is negligible. a) Draw a free body diagram of the force(s) acting on the ball at the bottom of the circle. Also include in your diagram any non-zero velocity and/or acceleration vector(s) of the ball. Label your coordinate system as the following: 0 Positive is towards the centre of the circle 0 Negative is away from the centre of the circle ' x ' \\ . + / i _ \"and; a d' l - ,2) Q" 1 n I e a l \"'3' M\" l l a WM '\\ I a ' ' Vertical Circular Motion Forces tutorial 8mm? b) At what location in the circle is the string most likely to break? Explain. The string of the ball is most likely to break when the ball is at the top of the vertical circle. This is because at the top of the circle, the tension force in the string is at its maximum, while the weight of the ball is at its minimum. The tension force is providing the centripetal force required to keep the ball moving in a circle, and it is equal to the sum of the gravitational force and the centrifugal force. If the tension force in the string exceeds the breaking strength of the string, the string will break at the top of the circle. See Lesson 2, P4 \"Applications of Circular Motion\c) The mass of the ball is 0.10 kg and the string is 45 cm long. If the tension in the string when the ball is at the top of the circle is 5.75 N, what is the speed of the (4) rock at that location? Fc = mxuc Please show diagram 1/4 FC = Tention : 5.75N ac = V/r 5.75N = (0.10kg)> v2 10.45m V12=r (Ft + mg)/m V 2 ( 5. 75 N x 0.45 m ) 10.10 kg V2 = 25.87 m2/ 52 V = J (25. 8 75 m 2 / s2) = 5.09 m/s5. A roller coaster car filled with passengers has a mass of 4800 kg. What speed must it have at the top of a 75.0 m-tall vertical circular loop in order for the car not to fall off the track? 0.5/2 diagram? 6. Use the following information to answers parts ac. A bucket filled with water has a mass of 4.54 kg. It is tied to a 65 cm-long rope that can withstand a force of 525 N. The bucket is spun at. a constant speed with a frequency of 2.0 Hz. a. Calculate the tension in the rope at the bottom of the circle. (2) Ft: 3 My l/r Fc = FT-Fg \\l _. 21}: \ (f See p.266 of textbook V = - 1'0 Is mama/5 F0 :: (4.5%)) C Si duh/5) 2/0-65/h it = 46 b {\\l [455.6032'1\"! N) b. Using only your answer from a, can you determine if the rope is strong enough to withstand the circular motion? Explain. (1) Yes, we can use the tension value that we found in part (a) to determine if the rope is strong enough to withstand the circular motion. The maximum tension that the rope can withstand is given as 525 N, and we found that the tension in the rope at the bottom of the circle is 466 N. Since the tension in the rope at the bottom of the circle is less than the maximum tension that the rope can withstand, we can conclude that the rope is indeed strong enough to withstand the circular motion. Use the information below to answer parts ag. A ball is attached to a string and swung in a horizontal circle at a constant speed. Assume air resistance is negligible. a) Draw a free body diagram of the force(s) acting on the ball in the horizontal plane. Also include in your diagram any non-zero velocity and/or acceleration vector(s) of the ball. Label your coordinate system as the following: 0 Positive is towards the centre of the circle 0 Negative is away from the centre of the circle 'l' 3 + F)\" in... \":1 \\j / a. K 17' " \\ - 74 l / \\ / mama \\ a a \\ .. >r "" 3 '1 4 #:W l ccn knead-me. 'Jl rm. f .r f K at 1 \\ I 5: .1 'I t... qua-mm. \"3'1