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Can someone solve and explain number 2 and 3, thanks! I need answer 2 and 3 answered this can be done with the graph and
Can someone solve and explain number 2 and 3, thanks!
I need answer 2 and 3 answered this can be done with the graph and excel.
Thin Lenses and Real Images DATA 10 cm double convex 20 cm double convex 1/y 1/ 35.3 40.7 42.3 45 48.7 53.4 Y 20.3 19.7 16.3 15 13.7 13.4 Hx 2.22 2.22 2.22 2.22 2.22 2.22 3.5 2 1 0.9 0.8 0.7 1/ 0.028 0.025 0.024 0.022 0.021 0.019 0.049 0.051 0.061 0.067 0.073 0.075 118.5 87.6 81.3 79.1 81.3 83.8 Y 103.5 57.6 46.3 39.1 36.3 33.8 Hx 2.22 2.22 2.22 2.22 2.22 2.22 7.8 3.3 2.7 1.7 1.5 1.3 0.0084 0.0114 0.0123 0.0126 0.0123 0.0119 1/y 0.0097 0.0173 0.0216 0.0256 0.0275 0.0296 x-object distance; y-image distance Hx-light source height, Hy- light image after being Casted EVALUATION OF DATA 1. Choose New from the File menu in the data-collection program. In the table, manually enter your data for your measurement with the 10 cm lens. Enter d-o (for object distance) and d- (for image distance) as the Names of the columns. 2. Examine your graph of image distance vs. object distance. What relationship appears to exist between these variables? Modify one of the variables so as to produce a linear graph: Choose New Calculated Column from the Table menu. After choosing a name and units for the column, select A/X as the Equation Type. Enter the column you wish to modify, then select OK. Tap the Graph tab and change the variable on the axis you have chosen to modify to see the resulting graph. You may find it necessary to modify the variables on both axes to linearize the graph. When you have done so, go to Analyze Menu / Curve fit and choose "linear. Write the equation of the best-fit line. 3. Examine the value and the units of the slope. Discuss with your instructor what the ideal value of the slope might be. Thin Lenses and Real Images DATA 10 cm double convex 20 cm double convex 1/y 1/ 35.3 40.7 42.3 45 48.7 53.4 Y 20.3 19.7 16.3 15 13.7 13.4 Hx 2.22 2.22 2.22 2.22 2.22 2.22 3.5 2 1 0.9 0.8 0.7 1/ 0.028 0.025 0.024 0.022 0.021 0.019 0.049 0.051 0.061 0.067 0.073 0.075 118.5 87.6 81.3 79.1 81.3 83.8 Y 103.5 57.6 46.3 39.1 36.3 33.8 Hx 2.22 2.22 2.22 2.22 2.22 2.22 7.8 3.3 2.7 1.7 1.5 1.3 0.0084 0.0114 0.0123 0.0126 0.0123 0.0119 1/y 0.0097 0.0173 0.0216 0.0256 0.0275 0.0296 x-object distance; y-image distance Hx-light source height, Hy- light image after being Casted EVALUATION OF DATA 1. Choose New from the File menu in the data-collection program. In the table, manually enter your data for your measurement with the 10 cm lens. Enter d-o (for object distance) and d- (for image distance) as the Names of the columns. 2. Examine your graph of image distance vs. object distance. What relationship appears to exist between these variables? Modify one of the variables so as to produce a linear graph: Choose New Calculated Column from the Table menu. After choosing a name and units for the column, select A/X as the Equation Type. Enter the column you wish to modify, then select OK. Tap the Graph tab and change the variable on the axis you have chosen to modify to see the resulting graph. You may find it necessary to modify the variables on both axes to linearize the graph. When you have done so, go to Analyze Menu / Curve fit and choose "linear. Write the equation of the best-fit line. 3. Examine the value and the units of the slope. Discuss with your instructor what the ideal value of the slope might be Step by Step Solution
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