Can someone solve this please! Thanks

Question 10 of 13 - / 20 E View Policies Current Attempt in Progress The angle (with respect to the vertical) of a simple pendulum is given by 6 = 9mc05[(5.88 rad/s)t + (pl. If at t = O, 9 = 0.0450 rad and de/dt = 0160 rad/s, what are (a) the phase constant (p and (b) the maximum angle 0,"? (Hint: Don't confuse the rate dG/dt at which 9 changes with the w of the SHM) (a) (a) Number I Unit V (b) Number a Unit v eTextbook and Media Save for Later Attempts: 0 of 5 used Using multiple attempts will impact your score. 10% score reduction after attempt 2