Can someone solve this problem?

(1 point) Check that the point (1, 1, 3) lies on the given surface. Then, viewing the surface as a level surface for a function at, 3;, z) = 1:, use gradient vector to find a vector normal to the surface and an equation for the tangent plane to the surface at (1,1,3). 3.732 23/2 + 322 = 28 vector normal = tangent plane: 2 = 1/9(3x+2y-22)