Can u just say if it's a b c or d 20-30

dthe.myschoolapp. What formula would be used to calculate the middle rectangle approximation of / (2x + 2)dx using five subintervals? 12.01 Semester Test: Calculus O Ms = (0.4)(12(0.4) + 2] + 2[(0.8) + 2] + 2[(1.2) + 2] + 2[(1.6) + 2] + 2[(2.0)+ 21} What is the Riemann sum that represents the illustration shown? The function is f (x) = Vx. Ms = (0.4)(12(0.0) + 2] + 2[(0.4) + 2] + 2[(0.8) + 2] + 2[(1.2) + 2] + 2[(1.6)+ 21} O Ms = (0.4)([2(0.2) + 2] + 2[(0.6) + 2] + 2[(1.0) + 2] + 2[(1.4) +2] + 2[(1.8)+ 21} O Ms = (0.2)(12(0.2) + 2] + 2[(0.6) + 2] + 2[(1.0) + 2] + 2[(1.4) + 2] + 2[(1.8)+ 21) 12.01 Semester Test: Calculus Reading VI . Ax; formula would be used to calculate the right rectangle approximation of fo (sin x . cos x)dix using four subintervals? I'Mw IMw I'M VXi RA = [sin(0) cos(0)] + [sin () cos ()] + [sin(x) cos(7)] + [sin () cos (")] R4 = (4) {Isin (4) cos (4)] + [sin (# ) cos (#)] + [sin (# ) cos (#) ] + [sin # cos #4 ] RA = () {[sin () cos ()] + [sin(x) cos(x)] + [sin ('# ) cos (*= )] + [sin(2x) cos(2m)]} EVxi . Axi RA = (E) { [sin(0) cos(0)] + [sin () cos ()] + [sin(z) cos(z)] + [sin (' ) cos ()1} Calculus hich of the following formula imation of So 2x dix using five subintervals ? T's = 0.4 [2(0.0) + 2(2)(0.4) + 2(2)(0.8) + 2(2)(1.2) + 2(2)(1.6) + 2(2.0)] Which integral would represent the area shown? The function is f(x) = -x2+ 5. O T's = 12(0.0) + 2(2)(0.4) + 2(2)(0.8) + 2(2)(1.2) + 2(2)(1.6) + 2(2.0)] O T's = 412(0.0) + 2(2)(0.4) + 2(2)(0.8) + 2(2)(1.2) +2(2)(1.6) + 2(2.0)] O Ts = 4[2(0.0) + 2(2)(0.4) + 2(2)(0.8) + 2(2)(1.2) + 2(2)(1.6) +2(2.0)1 05 1 h of the follow Created with a trial version of Advan te the trapezoid approximation of /, # dix using five subintervals? T's = 2 /10+ 2 (12) +2(15) +2(16) +2(18) +( 20)1 0 10 (-x2 ) dx T's = 92 ( 10 + 2 (12) + 2 (17 ) + 2 (15) + 2(18) + (25)1 0 12:24 ( x2 + 5) dx T's = 0.2 (10 + 2 ( 12) + 2 (17) +2(16) +2(18) + (20)1 TS = [To + 2 ( 12) + 2 ( 19) + 2(16) + 2 ( 15 ) + ( 20)1 0 1 5 ( x 2 + 5 ) dx 0 1 15 ( - x 2 + 5 ) dx What is the area of the integral of f (x) = 3 within the interval [1, 4]? 22 28 : Can the Fundamental Theorem of Calculus be used to find fo " sec x dx ? lus_06_01_ST_CO/ Yes, f(x) = So sec .x dx' is continuous on the given interval but its antiderivative does not exist. . No. f(x) = So sec x d.x is not continuous on the given interval and its antiderivative does not axis . No. f(x) = So sec.x d.x is not continuous on the given interval but its antiderivative exists. So 3 dx = 9 Yes, f (x) = fo sec x dix is continuous on the given interval and its antiderivati 0 fo 3 dx = 12 0 1 3 dx = 6 1 24 25 26 27 28 29 309 31 of 3 3 dx = 9 18 19 20 21 22 23 34 12.01 Semester Test: Calculus mmit.Calculus.04.at.ST.CO/cor MacBook Air What is the area of the integral of f(x) = 4 - X within the interval [0, 2]? 20-30 8 R T . So ( 4 + x)dx = 24 0 12 ( 4 + x )dx = 10 Evaluate Jo 8x3 dx . So ( 4 - x)dx = 9 0 81 0 1 2 ( 4 - x ) dx = 6 O 160 19 20 21 22 23 24 25 O 162 MacBook Air O 216