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can you help me with these f- 19 e charge = 1.602X10 c E = 3000 N/C E = 3008 N/C due to east Find
can you help me with these
\f- 19 e charge = 1.602X10 c E = 3000 N/C E = 3008 N/C due to east Find magnitude & direction west . e East of the electric force on an e.\f- 19 e charge = 1 . 602 x 10 ( 31 2 mass = 9. 1 1 x 10" kg Q = - 30 u c a ) Find humber electrons Jo ) Find how much doe her mass increaseStep by Step Solution
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