Can you help with part (d) and part (e) [the blank sections] of this calculus question.

Using the method of substitution, I2/m1(2+2m2)2dm=/f(u)du where 'u. : 2 + 2 * x\"? do: : 4x do: u) : u**2f4 Using the above information: [3% (2 + 2:1: 2)2d:1: : / f(u)du : (in terms of u) = (in terms of :12) Note: Don't forget the constant of integration in the last two blanks