Can you please 1. Recalculate the null and alternate hypothesis 2. Recalculate the upper and lower confidence interval According to the below suggestion " There is "-" in the claim, so HO=claim. You need to use mean and standard deviation of calls for 18people w/o training: 140. 9 and 9.71"

Mean 162.100000 Median 160.500000 Mode 131.000000 Variance 323.808081 Standard Deviation 17.994668 Range 71.0000 Count (n) 100 Min 130.000000 Quartile 1 149.000000 Median 160.500000 Quartile3 176.250000 Max 201.000000 Interquartile Range (IQR) 27.250000 I Hypothesis statement Mean calls made among those with no training is at least 145 Null and alternate hypothesis Ho=145 H1=>145 Type of test Hypothesis test on sample mean Use z or T Test Z Rejection region Reject {130-201} Test statistic 9.5 p-value 0.00 Hypothesis test result using P value The P value is less than the significant level, it is significant Hypothesis test result using test statistic The value falls into the rejection zone Do the results support the claim being made? yes 99% confidence interval for the mean Minimum is 157.46 ; upper is ; 166.73