Can you please explain the answer mentioned for part-a question few days back. While substituting inputs I am getting a different value instead of 7.68 kb/s?

a) The efficiency of the system if it operates in a simple "stop and wait" manner using positive acknowledgements can be calculated as follows: Data Length = 120 bytes Header Length = 8 bytes Frame Length = Data Length + Header Length = 120 bytes + 8 bytes = 128 bytes Channel Capacity = 64 kbit/s Service and Propagation Delay = 16 mSec Timeout Interval = 80 mSec Throughput = (Frame Length / (Timeout Interval + Service and Propagation Delay)) * Channel Capacity = (128 bytes / (80 mSec + 16 mSec)) * 64 kbit/s = 7.68 kbit/s

6. A data link protocol has the following characteristics: Data Length =120 bytes Header Length =8 bytes Channel Capacity =64kbit/s Ack. Frame Length =8 bytes Prob. of lost frame =2103 Prob. of lost Ack. =2104 Timeout Interval =80mSec Service and =16mSec Propagation Delay a) Estimate the efficiency of this system if the protocol operates in a simple "stop and wait" manner using positive acknowledgements