Question
Can you please explain to me how the value is .004?? This is a completed answer but I am unsure how the pvalue is .004.
Can you please explain to me how the value is .004?? This is a completed answer but I am unsure how the pvalue is .004.
- Use the percentages to the distribution of rural and urban communities
Catholic | Percentages | Protestant | Percentages | Other | Percentages | |
Favor legalization | 8 | 26.67 | 24 | 48 | 15 | 75 |
Oppose legalization | 22 | 73.33 | 26 | 52 | 5 | 25 |
Total | 30 | 100.00% | 50 | 100.00% | 20 | 100 |
b. the first step is to state the null hypothesis and an alternate-hypotheses.
H0 church and legalization are independent
H1church and legalization are not independent
Chi-square test for independence test
Give the data is as below
Matrix | column 1 | column 2 | olumn 3 |
row1 | 8 | 24 | 15 |
row2 | 22 | 26 | 5 |
Total | 30 | 50 | 20 |
Calculations for E table matrix
E-table | Column 1 | Column 2 | Column 3 |
row1 | row1 * col 1 / N | row1 * col 2 / N | row1 * col 3/ N |
row2 | row2 * col 1 / N | row2 * col 2 / N | row2 * col 3 / N |
Expected frequencies calculated by applying for E-table matrix formula
E-table | Column 1 | Column 2 | Column 3 |
Row1 | 14.1 | 23.5 | 9.4 |
Row2 | 15.9 | 26.5 | 10.6 |
Calculate chi-square test statistic using given observed frequencies.
Calculated expected frequencies from above
Oi | Ei | Oi - Ei | (Oi - Ei)2 | (Oi - Ei)2 /Ei |
8 | 14.1 | -6.1 | 37.21 | 2.639 |
24 | 23.5 | 0.5 | 0.25 | 0.010 |
15 | 9.4 | 5.6 | 31.36 | 3.336 |
22 | 15.9 | 6.1 | 37.21 | 2.340 |
26 | 26.5 | -0.5 | 0.25 | 0.009 |
5 | 10.6 | -5.6 | 31.36 | 2.958 |
Y2o = 11.293
Set up null vs alternative as:
Null, Ho: no relation between x and y or x and y are independent
Alternative: H1: exists a relation between x and y or x and y are dependent
Level of significance, alpha = 0.05
From the standard normal table, the chi-square value at right-tailed y2alpha/2 = 5.991
Since our test is right-tailed, reject Ho when y2> 5.991
We use test statistic y2 o =(Oi - Ei)2 /Ei
From the table, y2o = 11.293
Critical value
The value of y2 alpha at level of significance 0.05 with d.f (r - 1)(c - 1) = (2 -1) * (3-1)
= 2
We got [y2o] > y2 alpha and here we reject the null hypothesis
Y2p-value = (.003875) rounded to 0.004
Answer in summary:
Null, Ho: no relation between x and y or x and y are independent
Alternative: H1: exists a relation between x and y or x and y are dependent
Test statistic: 11.293
Critical value: 5.991
p-value: 0.004
decision: reject null hypothesis
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