Question
Can you please explane this assignment? It gave me error? Sign Guest Book
Can you please explane this assignment? It gave me error?
Unable to connect to the database servr.
" . "Error code " . mysql_errno() . ":" . mysql_errno(). "
";else { $DBName = "guestbook"; if (!@mysql_select_db($DBName, $DBConnect)){ $SQLstring = "CREATE DATABASE $DBName"; $QueryResult = @mysql_query($SQLstring, $DBConnect); if ($QueryResult === FALSE) echo "
Unable to execute the query.
" ."Error code" . mysql_errno($DBConnect) . ":" .mysql_error($DBConnect). "
"; else echo "You are the first visitor!
"; } mysql_select_db($DBName, $DBConnect);$TableName = "visitors"; $SQLstring = "SHOW TABLES LIKE '$TableName'"; $QueryResult = @mysql_query($SQLstring, $DBConnect); if (mysql_num_rows($QueryResult) == 0) { $SQLstring = "CREATE TABLE $TableName (countID SMALLINT NOT NULL AUTO_INCEMENT PRIMARY KEY, last_name VARCHAR(40), first_name VARCHAR(40))"; $QueryReult = @mysql_query($SQLstring, $DBConnect); if ($QueryResult===FALSE) echo "
Unable to create the table.
" . "Error code " . mysql_errno($DBConnect) . ":" . mysql_error($DBConnect). "
"; $LastName = stripslashes($_POST['last_name']); $FirstName = stripslashes($_POST['first_name']); $SQLstring = "INSERT INTO $TableName VALUES(NULL, 'LastName','$FirstName')"; $SQLstring = @mysql_query($SQLstring, $DBConnect); if ($QueryResult === FALSE) echo "Unable to execute the query.
" . "Error code" . mysql_errno($DBConnect) . ":" . mysql_error($DBConnect). "
"; else echo "Thank you signing our guest book!
"; } mysql_close($DBConnect) } } ?>Step by Step Solution
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