can you please help me answer these questions

Assume that iemales have pulse rates that are normally distributed with a mean of p = 76.0 beats per minute and a standard deviation of 5:12 5 beats per minute Complete parts (a) through (c) below. a. It 1 adult female is randomlyr selected, nd the probability that her pulse rate is between ?'0 beats per minute and 32 beats per minute. The probability is . (Round to four decimal places as needed.) b. tilt adult females are randomly selected, nd the probability that they have pulse rates with a mean between 70 beats per minute and 32 beats per minute. The probability is . (Round to four decimal places as needed.) 1:. Why can the normal distribution be used in part {b}, even though the sample size does not exceed 3|]? 0 A. Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size. 0 B. Since the mean pulse rate exceeds 30. the distlibution of sample means is a normal distribution for any sample size. 0 C. Since the distribution is of individuals, not sample means, the distribution is a normal distribution for any sample size. 0 D. Since the distribution is of sample means, not individuals, the distribution is a normal distribution for any sample size. Assume that adults have IQ scores that are normally distributed with a mean of 103.8 and a standard deviation 18.7. Find the first quartile Q, which is the IQ score separating the bottom 25% from the top 75%. (Hint: Draw a graph.) The first quartile is. (Type an integer or decimal rounded to one decimal place as needed.)In a survey of 3191 adults aged 57 through 85 years, it was found that 81.3% of them used at least one prescription medication. Complete parts (a) through (c) below. a. How many of the 3191 subjects used at least one prescription medication? (Round to the nearest integer as needed.) b. Construct a 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication. %

that corresponds to the given confidence level. 87% Za/2 = Round to two decimal places as needed.)