Can you solve the questions that didn't get full marks please (for questions 3 full page needs revision)

3. A girl on a sledge starts from rest at a height of 3.4 meters above a horizontal region of snow as shown in the hi diagram below. The mass of the sledge and girl combination is 64.5 kg. Sketch pie charts here. -sledge O h =3.4 m snow slope horizontal region of snow a. Use energy concepts to calculate the speed of the girl and sledge combination as she enters the horizontal region of snow assuming a closed, isolated system. 2 (2 pts) / b. Assume instead of a closed, isolated system the girl and sledge arrive at the horizontal region with 20% less energy than she started with beginning height. Describe what happened to the missing mechanical energy in the space below. Then sketch and label energy pie charts for the beginning and horizontal motion locations on the diagram above. A E. mech. E thermal or Sand ......>.. (2 pts) c. At one point on the horizontal region of snow the girl and sledge are moving at 4.80 m/s. The force of friction then brings the combination of girl and sledge to rest over a distance of 9.75 m. Determine the force of friction acting on the sledge assuming it is constant. (Ignore air resistance in this calculation). from AEK = W-7 Ep = 76. 2 N .......... .(2 pts) d. The girl now at rest on the level surface pushes her foot against the snow to get her and the sledge moving again. She applies a constant force over a 9.4 second time interval and reaches a final speed of 3.2 m/s. Determine the power generated by the girl during the period of the accelerated motion. P = RE = 35W ......... (2 pts) 3need in a holder II in he spring is released k loses ice block is pl eft. When t ssed, the ice bloc a truck. The pushing H to the l decomprc 2. A company designs a spring system for loading ice blocks OHIO front of the spring and an electric motor compresses the spring by _ the ice block is accelerated tonards a ramp ABC. When the spring is Fully contact with the spring at A. The mass of each ice block is 60.0 kg. spring ice block a. The graph below shows how the spring force varies over the distance of compression ofthe Spring- 3200 Force (N) Compression 0 Distance (m) 0 0.5 D Use the graph to calculate the \\\\ ork done on the spring during the compression process. \\Ilt: \\ % c. The energy stored in the spring in part b) is used to launch a block of ice up the ramp. Use energy concepts to M "calculate the speed of the ice block at point C assuming a closed, isolated system. he 8 pt C/ goosegm\" + mg ...................... l .......................... ........-......................... ......._....._._.._....:::iI:I:l:il.ll:::':.'_'.'.'.i.li.l.ii_i}'ii%99ny ........... Z7V' .................................................... 1%9lw'0vvfgsm/'(Z pts)! (1. At point C the block from your calculation in part c undergoes an elastic collision with a second ice block of the same mass and immediately stops. Calculate the momentum of the block before the collision and detemiine the .he impulse supplied by the rst ice block on the second ice block during the collision. FAT\" A A =\\OCpt\\t-s C ................................................. P (1 pt) ' 2 gm 1. (2.4) This question is about momentum and its conservation. a. Define force for topic 2.4 F = Ap/ At in words Force Is A momentum by a certain amount of time, . ( 1 pt ) . 5 A 15,000 kg box car is moving along a railroad track at 4.3 m/s until it collides and couples to a 9,500 kg gondola and isolated. that is initially at rest. The coupled cars then move along the track as a single unit. Assume the system is closed 15,000 Box car, u = 4.3 m/s 9500 gondola, initially at rest b. Describe the condition(s) for a system of interacting objects to be consider a closed, isolated system. Some Conditions are! to external forces . ....... ........... . . . . . . . . . . (1 pt) | c. Calculate the velocity of the coupled cars as they move as one unit after the collision. MA: VA.= (Ma + Mb.). Vboth . . . . . . ... (15000) ((4: 3mk ) - ( 24500) uboth 64500 =(24500 ) moth .. Vooth : 2.63 mls 24500 d. Calculate the kinetic energy of the cars before and after the collision and name the type of collision (elastic or inelastic) that has occurred. . . . . . . . . ...... EKi= 2 mv z EKf = = ( 24500 ) ( 2 .63 ) ? E.k.: 2 ( 15,000) (4, 3 ) 2 Eke: 84732 .. inelastic ....... Ekin 13, 86757. Hit and stick collision (3 pts ) 3 e. The cars then run onto a rough patch of rail where a friction force of 1,500 N works against the motion of the cars for 12 seconds. Determine the impulse applied to the cars by friction during this time. . . . . . FAT 1500. 12 seconds = 18,000 . . . . . . . .. ... ................... (1 pt) / State the change of momentum of the cars during this 12-s time interval. . . . .. . . .. ....... 10 - mblank . Ap = also . . . . . . . ... (1 pt) O 1 7.5c) A lab group calculated the slope of their best fit line and got 0.955. Comment on this value and what it indicates about conservation of momentum for this lab group. (2 marks) The slope indicates the change in * momentum. slope = lif Epi = zpe 2. For one of the trials the following mass and velocity was recorded: Starting Mass = 0.517 kg Initial Velocity = 1.16 m-s'] Final Mass = 2.024 kg Final Velocity = 0.285 m-5 1 Calculate the following: A. The initial kinetic energy (1 mark) Ekit ( 0.517 ) ( 1 16) - 3408 J Re do these calculation's You #'s are look toobig a B. The final kinetic energy (1 mark) EKf - } ( 2 02 4) ( 0. 285) 2 6 0802 2 J C. The efficiency of the system ( 1 mark ) out -* 100 8.22 in 34. 8 * 100 = 24.1 b) What type of interaction is this? A.) Elastic B. Inelastic C Explosion (1 mark) O c) Explain the difference in the initial and final energy values. (1 mark) . the system started at a high kinetic energy then it decreased by a great amant at the end AE - Eheat much Esand 1 imp 3 or w to do form