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Can you solve this problem step by step. Q1-(25 pts) A 2 mm air-gap parallel plate capacitor with capacitance Cy = 6 mF is connected

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Q1-(25 pts) A 2 mm air-gap parallel plate capacitor with capacitance Cy = 6 mF is connected to an ideal battery of 8 V. Then, a dielectric slab of thickness 1mm with dielectric constant K = 2 is inserted to completely occupy the lower right quarter of the space between the plates of the capacitor, as shown. before after | = T d=2mm _Bv ~ a) Calculate the capacitance of the capacitor with the dielectric slab in place. b) Calculate the total charge stored in the capacitor with the dielectric slab. c) Calculate the amount of work required to remove the dielectric slab from the capacitor. W=

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