Can you tell me the formulas I would need to calculate this table?

B. Buoyant Force on Light Obj Table 3 Block A Material = Muminum WAQ = 59.92 N WAS = 33.13 N Table 4 Block B Material ice W Ba = 18.0IN WABS= 31.36N WRS = -1.59N FBb = 19.6N Wwater 16.60 % difference = 0 .1 Table 5 Block B Material = vood W Ba = 1.84M WABS= 21.56N WRS = -14.16 m FBh = 19.6 N Wwater = 14.6N % difference = 0 .1. Table 6 Block B Material = styrofo W Ba 2.94 N WABS= 16.66N WBS -16.60N FBb = 19-6N Wwater = 19. GN % difference = 0.10