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Canceling the mass m, we find GM (6.67 x 10 N . m /kg )(5.97 x 10#4 kg) 12-4 (6.37 x 10* m) - 9.61

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Canceling the mass m, we find GM (6.67 x 10" N . m /kg )(5.97 x 10#4 kg) 12-4 (6.37 x 10* m) - 9.61 m/s This result can be extended to objects above the Earth's surface, and hence farther from the center of the Earth, as we show in the next Example. DENCE OF GRAVITY ON ALTITUDE Everest, you will be about celeration due to gravity at. Question 15 (1 point) Retake question Calculate the acceleration of gravityr at the surface of a planet of mass 3.00 x 1024 kg and radius 4,070 km. Express your answer in mrsz. Use Eq. 12-4. Make sure you convert kilometers to meters

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